101*x^2-200*x+99=0

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Solution for 101*x^2-200*x+99=0 equation: 



101x^2-200x+99=0

a = 101; b = -200; c = +99;
Δ = b2-4ac
Δ = -2002-4·101·99
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-2}{2*101}=\frac{198}{202}
=99/101
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+2}{2*101}=\frac{202}{202}
=1
$

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